How to use Try Catch Exception in Laravel App?

Hi Dev,

This tutorial shows you laravel try catch in controller. you can see how to use try catch in laravel controller. this example will help you laravel try catch exception not working. I’m going to show you about try catch laravel example. Alright, let’s dive into the steps.

Why do we need to use try-catch in our php laravel app?, I will explain you why. Sometimes we wrote code right but there is a possibility where the user input the wrong data or something will wrong on the website then our user should not show an error, we can handle the error and display proper message where is a issue and what they need to do. so same thing whenever you need to use try-catch then you can easily use like bellow example, you can use this example in laravel 6, laravel 7, laravel 8 and laravel 9 versions.

Let’s see below syntax and example:


You have to use try catch as below syntax and you must need to use “use Exception” on top of file in laravel.

try {

/* Write Your Code Here */

} catch (Exception $e) {

return $e->getMessage();



Here, i will show you controller file code and we will use “$input” variable in controller method that not define any more. it will generate error. so let’s see bellow example:


namespace AppHttpControllers;

use IlluminateHttpRequest;

use AppModelsUser;

use Exception;

class UserController extends Controller



* Display a listing of the resource.


* @return IlluminateHttpResponse


public function show($id)


try {

$user = User::find($input['id']);

} catch (Exception $e) {

$message = $e->getMessage();

var_dump('Exception Message: '. $message);

$code = $e->getCode();

var_dump('Exception Code: '. $code);

$string = $e->__toString();

var_dump('Exception String: '. $string);



return response()->json($user);




string(44) "Exception Message: Undefined variable $input"

string(17) "Exception Code: 0"

string(17) "Exception String: ......"

I hope it can help you…

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